Match the following with its correct value of PA nbsp-6cm10cm4cm

The correct option is PD× PC = PA× PB 6× 25 = 15× PA PA= 10cm PC× PD= PB × PA 7× 12= 14 × PA PA=6cm PT^2 = PA× PB 6^2 = PA× (PA +5) 36 = (PA)^2+5PA) Let ...

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Standard X

Mathematics

Relation between Tangent and Intersecting Line

Match the fol...

Question

Match the following with its correct value of PA

6cm

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10cm

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4cm

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Solution

$P D \times P C = P A \times P B$
$6 \times 25 = 15 \times P A$
$P A = 10 c m$

$P C \times P D = P B \times P A$
$7 \times 12 = 14 \times P A$
$P A = 6 c m$

$P T^{2} = P A \times P B$
$6^{2} = P A \times (P A + 5)$
$36 = (P A)^{2} + 5 P A)$
Let
PA be x
So,
$36 = x^{2} + 5 x)$
$x^{2} + 5 x - 36 = 0$
$(x + 9) (x - 4)$
x= -9,4
So, x=4cm { as the value of PA can not be negative }

$P A = 4 c m$

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Match the following with its correct value of PA

PD×PC=PA×PB 6×25=15×PA PA=10cm PC×PD=PB×PA 7×12=14×PA PA=6cm PT2=PA×PB 62=PA×(PA+5) 36=(PA)2+5PA) Let PA be x So, 36=x2+5x) x2+5x−36=0 (x+9)(x−4) x= -9,4 So, x=4cm { as the value of PA can not be negative } PA=4cm