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Question

Match the following with the value of a2+1a2 for the conditions given below.

A
14
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B
34
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C
27
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D
11
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Solution

Using the identity,
(a+b)2=a2+2ab+b2,
a2+b2=(a+b)22ab.

So, a2+1a2=(a+1a)22

(i) Given that a+1a=4
a2+1a2=(a+1a)22=422
a2+1a2=162=14

(ii) Given that a+1a=6
a2+1a2=(a+1a)22=622
a2+1a2=362=34

​Using identity,
​​​​​​(ab)2=a22ab+b2,
a2+b2=(ab)2+2ab.
So,​​​​​ a2+1a2=(a1a)2+2

(iii) Given that a1a=5
a2+1a2=(a1a)2+2=52+2=27

(iv) Given that a1a=3
a2+1a2=(a1a)2+2=32+2=11

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