Question

Match the following with their minimum and maximum oxidation number if any as well as with their respective variable oxidation number if any.

Answer 1

$A:N$ has lowest oxidation state of $0$ in $N_2$ element. and highest oxidation state of $+5$ in $HN{O}_3$, and other O.S. are $-1/3$ in $H{N}_3$, and $+3$ is found in $HN{O}_2$.

$B:N$ has lowest oxidation state of $0$ in $P_4$ element and highest oxidation state of $+5$ in $PC{l}_5$ and $+3$ is found in $PC{l}_3$.

$C:Mn$ in elemental form has $0$ oxidation state, $Mn$ has $+3$ oxidation state in $M{n}_2{O}_3$, and $+5$ in $M{n}_2{O}_5$, whereas it has $+7$ in $M{n}_2{O}_7$, which is very covalent and $+4$ in $M{n}_2{O}_4$.

$D:C$ has $0$ in elemental form, $+4$ in $CC{l}_4$ and $-4$ in $C{H}_4$.

$E:Bi$ has $0$ in elemental form, $+3$ in $BiC{l}_3$ and $+5$ in $Bi{F}_5$.

$F:Cl$ has $0$ in $C{l}_2$ element and $+3$ in $HCl{O}_2$,$+5$ in $HCl{O}_3$, $+7$ in $HCl{O}_4$, and $+4$ in $C{l}_2{O}_7$.