Match the following
a) step up transformer d) turns ratio is 1
b) step down transformer e) Ns > Np
c) Ideal transformer f) Np > Ns

a-f, b-e, c-d

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a-e, b-d, c-f

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a-d, b-e, c-f

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a-e, b-f, c-d

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Solution

The correct option is C a-e, b-f, c-d
Step up transformers $E s > E p$
So, $N s > N p$ $(∵ \frac{E s}{E p} = \frac{N s}{N p})$
Step down transformers $E x < E p$
So, $N s < N p$
deal transformers $E s = E p$
So, $N s = N p$
or, turns ratio $= 1$

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Similar questions

In a step up transformer :
(a) $N_{s} = N_{p}$ (b) $N_{s} < N_{p}$
(c) $N_{s} > N_{p}$ (d) nothing can be said.

\frac{E_{p}}{E_{s}} = \frac{n_{s}}{n_{p}}

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