Match the followings :

LIST 1 LIST 2
A
Man 1 Poceae
B Datura 2 Anaerdiaceae
C Mango 3 Solanaceae
D Wheat 4 Hominidae

A - 4, B - 3, C - 2, D - 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A - 3, B - 4, C - 1, D - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A - 2, B - 4, C - 3, D - 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A - 4, B - 3, C - 1, D - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A A - 4, B - 3, C - 2, D - 1
So the correct option is 'A-4.B-3,C-2,D-1'.
LIST 1 LIST 2 (families)
1 Man Hominidae
2 Datura Solanaceae
3 Mango Anaerdiaceae
4 Wheat Poaceae

Suggest Corrections

Similar questions

\int_{- 1}^{4} f (x) d x = 4

\int_{2}^{4} [3 - f (x)] d x = 7 t h e n \int_{- 1}^{2} f (x) d x =

List I	List II
I. $\int_{- 1}^{1} x \| x \| d x$	(a) $\frac{π}{2}$
II. $\int_{0}^{\frac{π}{2}} (1 + log (\frac{4 + 3 sin x}{4 + 3 cos x})) d x$	(b) $\int_{0}^{\frac{a}{2}} f (x) d x$
III. $\int_{0}^{a} f (x) d x$	(c) $\int_{0}^{a} [f (x) + f (- x)] d x$
IV. $\int_{- a}^{a} f (x) d x$	(d) $0$
	(e) $\int_{0}^{a} f (a - x) d x$

$I f \int_{2}^{4} f (x) d x = \frac{1}{2} a n d f (6 - x) = f (x), t h e n \int_{2}^{4} x f (x) d x =$

\int_{0}^{π / 2} \frac{d x}{1 + {tan}^{5} x} = \frac{π}{4}

\int_{0}^{a} f (x) d x = \int_{0}^{a} f (a + x) d x = \int_{0}^{π / 2} \frac{d x}{1 + {tan}^{3} x} = \int_{0}^{π / 2} \frac{d_{X}}{1 + {cot}^{3} x} = \frac{π}{4}

Join BYJU'S Learning Program