Distance between two points A(x1,y1) and B(x2,y2) is given as
AB =√(x2−x1)2+(y2−y1)2
i) A(3, 4) and B(4,5)
AB is the distance between the points A and B.
AB =√(4−3)2+(5−4)2 = √1+1= √2
AB = √2 units
ii) P(4,5) and Q(5,5)
PQ is the distance between the points P and Q.
PQ =√(5−4)2+(5−5)2 = √1+0= 1
PQ = 1 unit
iii) E(6,3) and F(7,8)
EF is the distance between the points E and F.
EF =√(7−6)2+(8−3)2 = √1+25= √26
EF= √26 units
iv) M(1,2) and N(3,8)
MN is the distance between the points M and N.
MN=√(3−1)2+(8−2)2 = √4+36= √40
EF= √40 = √4×10 = 2√10 units