Match the group A with result in group BGroup AGroup B1- Number of molecules present in 88 g of CO2-a 4-25g2- Number of moles in 128 of SO2-b 28-4g3- Weight of 5-6 litres of NH3-c 12-044 10234- Volume occupied by 46 g NO2-d 22-4 itres 5- Mass of 0-4 moles of Cl2-e 2 moles6- Atoms in 18 g of water-f 18-066 x 1023

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Byju's Answer

Standard XII

Chemistry

Isobars and Isotopes

Match the gro...

Question

Match the group A with result in group B
Group A Group B
1. Number of molecules present in 88 g of CO₂. (a) 4.25g
2. Number of moles in 128 of SO₂. (b) 28.4g
3. Weight of 5.6 litres of NH₃. (c) 12.044 10²³
4. Volume occupied by 46 g NO₂. (d) 22.4 itres
5. Mass of 0.4 moles of Cl₂. (e) 2 moles
6. Atoms in 18 g of water. (f) 18.066 x 10²³

Column 1 Column 2

Group A
Number of molecules present in 88 g of CO₂.

Group B Region
4.25g
Mole mass is 5.6 ÷ 22.4 =0.25
Then weight is (34 x 0.25) ÷ 2 = 4.25 g

The number of moles in 128g of SO₂.

28.4g
The total number of moles is 2.
Mass of 1 mole is 35g.

Weight of 5.6 liters of NH₃.

12.044 10²³
The total number of moles are 88 ÷ 44 =2
Then, the total number of molecules are.

Volume occupied by 46 g NO₂.

22.4 itres
The molecular mass of NO₂ (Nitrogen Dioxide) is 46,
The total number of moles is 1 mole.

Mass of 0.4 moles of Cl₂.

2 moles
The molar mass of SO₂ is 64
The number of moles in 64 g is 1 mole

Atoms in 18 g of water.

18.066 x 10²³
There are 3 moles in the water.
18 gm of water have 6.023 × 10²³ molecules.
so, The total atoms are 18.069 × 10²³ atoms.

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Solution

All needed explanation is done in the region section

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Group A	Group B
1. Number of molecules present in 88 g of CO₂.	(a) 4.25g
2. Number of moles in 128 of SO₂.	(b) 28.4g
3. Weight of 5.6 litres of NH₃.	(c) 12.044 10²³
4. Volume occupied by 46 g NO₂.	(d) 22.4 itres
5. Mass of 0.4 moles of Cl₂.	(e) 2 moles
6. Atoms in 18 g of water.	(f) 18.066 x 10²³