Match the group A with result in group B
Group A | Group B |
1. Number of molecules present in 88 g of CO2. | (a) 4.25g |
2. Number of moles in 128 of SO2. | (b) 28.4g |
3. Weight of 5.6 litres of NH3. | (c) 12.044 1023 |
4. Volume occupied by 46 g NO2. | (d) 22.4 itres |
5. Mass of 0.4 moles of Cl2. | (e) 2 moles |
6. Atoms in 18 g of water. | (f) 18.066 x 1023 |
Column 1 | Column 2 |
Group A | Number of molecules present in 88 g of CO2. |
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Group B | Region | 4.25g | Mole mass is 5.6 ÷ 22.4 =0.25 Then weight is (34 x 0.25) ÷ 2 = 4.25 g |
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The number of moles in 128g of SO2. |
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28.4g | The total number of moles is 2. Mass of 1 mole is 35g. |
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Weight of 5.6 liters of NH3. |
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12.044 1023 | The total number of moles are 88 ÷ 44 =2 Then, the total number of molecules are . |
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Volume occupied by 46 g NO2. |
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22.4 itres | The molecular mass of NO2 (Nitrogen Dioxide) is 46, The total number of moles is 1 mole. |
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Mass of 0.4 moles of Cl2. |
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2 moles | The molar mass of SO2 is 64 The number of moles in 64 g is 1 mole |
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18.066 x 1023 | There are 3 moles in the water. 18 gm of water have 6.023 × 10²³ molecules. so, The total atoms are 18.069 × 10²3 atoms. |
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