Question

Match the increasing orders given in column I with the property(ies) given in column II.

Column I	Column II
(A) $N{a}^{+}<F^{-}<O^{2-}<N^{3-}$	(p) electronegativity
(B) $L{i}^{+}$ < $N{a}^{+}$ < $K^{+}$ < $R{b}^{+}$ < $C{s}^{+}$	(q) Ionisation energy
(C) $O<S<F<Cl$	(r) Size
(D) $C{l}^{-}<K^{+}<C{a}^{2+}<S{c}^{3+}$	(s) Electron affinity

• A. (A-r) ; (B-r) ; (C-s) ; (D-p, q, s)
• B. (A-r) ; (B-r) ; (C-s) ; (D-p, q, s)
• C. (A-r) ; (B-r) ; (C-s) ; (D-p, q, s)
• D. (A-r) ; (B-q) ; (C-s) ; (D-p, q, s)

Answer 1

The correct option is C (A-r) ; (B-r) ; (C-s) ; (D-p, q, s)

(A-r) ; (B-q,r) ; (C-s) ; (D-p, q, s, t)
(A-r) For isoelectronic species, the ionic size decreases with increase in nuclear charge. correct order of anionic size is $N{a}^{+}<F^{-}<O^{2-}<N^{3-}$
(B- r) Number of atomic shells increases, ionic size increases.
correct cationic size is $L{i}^{+}$ < $N{a}^{+}$ < $K^{+}$ < $R{b}^{+}$ < $C{s}^{+}$
(C-s) Correct order ; as Cl has less inter electronic repulsions than F due to bigger size of 3p- subshell so, the correct order of electron affinity is $O<S<F<Cl$
(D- p,q,s)
$C{l}^{-}<K^{+}<C{a}^{2+}<S{c}^{3+}$
Oxidation state increases, the electronegativity increases. For isoelectronic species ionisation energy and electron affinity increases with increasing nuclear charge.