Question

Match the information given in the three columns of the following table. The only combination in which $C{O}_2$ is passed for neutralization is:

Column 1: Metal

Column 2: Ores

Column 3: Composition

$\begin{array}{cccccc}& \text{Column 1}& & \text{Column 2}& & \text{Column 3}\\ \left(I\right)& \text{Aluminium}& \left(i\right)& \text{Haematite}& \left(P\right)& CuFe{S}_2\\ \left(II\right)& \text{Iron}& \left(ii\right)& \text{Zinc blende}& \left(Q\right)& Al{O}_x(OH{)}_{3-2x}\\ \left(III\right)& \text{Copper}& \left(iii\right)& \text{Bauxite}& \left(R\right)& F{e}_2{O}_3\\ \left(IV\right)& \text{Zinc}& \left(iv\right)& \text{Copper pyrite}& \left(S\right)& ZnS\end{array}$

• A. (II) (iv) (S)
• B. (I) (iii) (S)
• C. (I) (iv) (P)
• D. (I) (iii) (Q)

Answer 1

The correct option is D (I) (iii) (Q)

Aluminium, Bauxite, $Al{O}_x(OH{)}_{3-2x}$

$A{l}_2{O}_3+2NaOH\to 2NaAl{O}_2+H_{2}O$

$2NaAl{O}_2+3H_{2}O+C{O}_2\to 2Al(OH{)}_3+N{a}_{2}C{O}_3$