Question

Match the interhalogen compounds of column - I with the geometry in column - II and assign the correct code.
$\begin{array}{cccc}& ColumnI& & ColumnII\\ \left(A\right)& X{X}^{\prime }& \left(i\right)& T-shape\\ \left(B\right)& X{X}_3^{\prime }& \left(ii\right)& Pentagonalbipyramidal\\ \left(C\right)& X{X}_5^{\prime }& \left(iii\right)& Linear\\ \left(D\right)& X{X}_7^{\prime }& \left(iv\right)& Squarepyramidal\\ & & \left(v\right)& Tetrahedral\end{array}$

• A. a - (iii); b - (i); c - (iv); d - (ii)
• B. a - (v); b - (iv); c - (iii); d - (ii)
• C. a - (iv); b - (iii); c - (ii); d - (i)
• D. a - (iii); b - (iv); c - (i); d - (ii)

Answer 1

The correct option is A a - (iii); b - (i); c - (iv); d - (ii)

Halogens have 7 electrons in their last shell.
$X{X}^{\prime }$ would have a linear structure
$X{X}_3^{\prime }$ would have a T shape structure and NOT triangular planar due to the lone pair of electrons (2 pairs)
$X{X}_5^{\prime }$ would have one lone pair and would be square pyramidal (lone pair on axial plane).
$X{X}_7^{\prime }$ would have no lone pairs and would be pentagonal bypiramidal.