Question

Match the interhalogen compounds of column I with the shapes in column II and assign the correct code.

Column I	Column II
a. $X{X}^{\prime }$	(i) T-shape
b. $X{X}_3^{\prime }$	(ii) Pentagonal bipyramidal
c. $X{X}_5^{\prime }$	(iii) Linear
d. $X{X}_7^{\prime }$	(iv) Square pyramidal
	(v) Tetrahedral

• A. $a-\left(iii\right),b-\left(iv\right),c-\left(i\right),d-\left(ii\right)$
• B. $a-\left(iii\right),b-\left(i\right),c-\left(iv\right),d-\left(ii\right)$
• C. $a-\left(v\right),b-\left(iv\right),c-\left(iii\right),d-\left(ii\right)$
• D. $a-\left(iv\right),b-\left(iii\right),c-\left(ii\right),d-\left(i\right)$

Answer 1

The correct option is B $a-\left(iii\right),b-\left(i\right),c-\left(iv\right),d-\left(ii\right)$

(a)-(iii),
$X{X}^{\prime }$ has linear shape as only two atoms are present.

(b)−(i),
$X{X}_3^{\prime }$ has T-shaped as 3 bond pairs and 2 lone pairs of electrons are present. The electron pair geometry is trigonal bipyramidal.

(c)−(iv),
$X{X}_5^{\prime }$​ has square pyramidal shape as 5 bond pairs and 1 lone pair of electrons are present. The electron pair geometry is octahedral.

(d)−(ii)
$X{X}_7^{\prime }$ has pentagonal bipyramidal shape as 7 bond pairs and 0 lone pairs of electrons are present.
Hence, option (B) is the correct answer.