Question

Match the intermediates given in column I with their probable structure in column II.

	Column I		Column II
A	Free Radical	$\left(i\right)$	Trigonal planar
B	Carbocation	$\left(ii\right)$	Pyramidal
C	Carbanion	$\left(iii\right)$	Linear

Answer 1

(A) Free radical

Hybridisation of central carbon $-s{p}^2$
Shape – trigonal planar ( because all the carbon-alkyl bonds lies in a single plane )

Hence, the correct match is:

$\left(A\right)\to \left(i\right)$

(B) Carbocation

Hybridisation of central carbon $s{p}^2$
Shape – trigonal planar ( because all the carbon-alkyl bonds lies in a single plane )

Hence, the correct match is:

$\left(B\right)\to \left(i\right)$

(C) Carbanion

Hybridisation – $s{p}^3$

Shape – pyramidal ( because all the carbon-alkyl bonds form a pyramidal )

Hence, the correct match is:

$\left(C\right)\to \left(ii\right)$

So, the correct matches can be represented as:

$\left(A\right)\to \left(i\right)$,$\left(B\right)\to \left(i\right)$,$\left(C\right)\to \left(ii\right)$