Question

Match the ionization processes listed in column-I with the changes observed as listed in column - II. For this use the codes given below:
$\begin{array}{cc}\text{Column-I}& \text{Column-II}\\ \left(a\right)N_2\to N_2^{+}& \left(p\right)\text{Bond order increases and magnetic property is changed}\\ \left(b\right)O_2^{+}\to O_2^{2+}& \left(q\right)\text{Bond order decreases and magnetic property is not changed}\\ \left(c\right)B_2\to B_2^{+}& \left(r\right)\text{Bond order increases and magnetic property is not changed}\\ \left(d\right)N{O}^{-}\to NO& \left(s\right)\text{Bond order decreases and magnetic property is changed}\end{array}$
Note: Here change in magnetic property refers to change from diamagnetic to paramagnetic or paramagnetic to diamagnetic.

• A. $\begin{array}{cccc}a& b& c& d\\ s& p& r& q\end{array}$
• B. $\begin{array}{cccc}a& b& c& d\\ s& p& q& r\end{array}$
• C. $\begin{array}{cccc}a& b& c& d\\ r& q& s& p\end{array}$
• D. $\begin{array}{cccc}a& b& c& d\\ p& s& q& r\end{array}$

Answer 1

The correct option is B $\begin{array}{cccc}a& b& c& d\\ s& p& q& r\end{array}$

$\left(a\right)N_2=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^2=\pi 2p_y^2\sigma 2p_z^2$
$B.O.=\frac{10-4}{2}=3;n=0\left(D\right)$
$N_2^{+}=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^2=\pi 2p^2{p}_y^2\sigma 2p_z^1$
$B.O.=\frac{9-4}{2}=2.5;n=1\left(P\right)$
$\left(b\right)O_2^{+}=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2=\pi 2p_y^2{\pi }^{\ast }2p_x^1={\pi }^{\ast }2p_y^0$
$B.O.=\frac{10-5}{2}=2.5;n=1\left(P\right)$
$O_2^{2+}=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2=\pi 2p_y^2{\pi }^{\ast }2p_x^0={\pi }^{\ast }2p_y^0$
$B.O.=\frac{10-4}{2}=3;n=0\left(D\right)$
$\left(c\right)B_2=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^1=\pi 2p_y^1$
$B.O.=\frac{6-4}{2}=1;n=2\left(P\right)$
$B_2^{+}=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_x^2=\pi 2p_y^1\sigma 2p_z^0$
$B.O.=\frac{5-4}{2}=1/2;n=1\left(P\right)$
$\left(d\right)N{O}^{-}=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^1=\pi 2p_y^2{\pi }^{\ast }2p_x^1={\pi }^{\ast }2p_y^1$
$B.O.=\frac{10-6}{2}=2.0;n=2\left(P\right)$
$NO=\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\sigma 2p_z^2\pi 2p_x^2=\pi 2p_y^2\sigma \ast 2p_x^1={\pi }^{\ast }2p_y^0$
$B.O.=\frac{10-5}{2}=2.5;n=1\left(P\right)$