Question

Match the item under List (I) with items under List (II).

Answer 1

We need to find the coordination number of all the molecules based on that we can easily determine its shape.

(A) ${PCl}_5$

Coordination number $=\frac{5+7\times 5}{8}=5$

This means ${PCl}_5$ hybridisation is ${sp}^{3}d$

Hence, its shape is trigonal bipyramidal.

(B) $F_{2}O$

$V-$ shape due to $2$ lone pairs.

(C) ${BCl}_3$

Coordination number $=\frac{3+7\times 3}{8}=3$

This means ${BCl}_3$ hybridisation is ${sp}^2$

Hence, its shape is trigonal planar.

(D) ${NH}_3$

Its shape is trigonal pyramidal as it has $1$ lone pair.