Match the items of Column I with the items of Column II.

Column - I Column - II

a. Large crystals i. Turns lime water milky

b. Depositing a layer of zinc on iron ii. Physical change

c. Souring of milk iii. Rust

d. Carbon dioxide iv. Carbon dioxide

e. Iron oxide v. Chemical change

f. Dissolving common salt in water vi. Galvanisation

a - iv, b - vi, c - v, d - i, e - iii, f - ii

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Solution

The correct option is A a - iv, b - vi, c - v, d - i, e - iii, f - ii
(a) Large crystals - (iv)
Sugar candy (Mishri) exists in a large crystal form.
(b) Depositing a layer of zinc on iron - (vi)
Galvanisation is the process of depositing a layer of zinc on iron, to prevent iron from rusting.
(c) Souring of milk - (v)
Souring of milk is a chemical change as chemical characteristics like taste of milk changes which can not be reversed back.
(d) Carbon dioxide - (i)
Carbon dioxide turns lime water milky.
$C O_{2}$ + Lime water $[C a (O H)_{2}]$
$\to$ Calcium Carbonate $C a C O_{3}$ [white]
$\to$ Water $(H_{2} O)$
(e) Iron oxide - (iii)
Iron on exposure to moisture and air, forms iron oxide also known as rust.
(f) Dissolving common salt in water - (ii)
Dissolving common salt in water is a physical change which can be reversed to obtain the salt back.

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Temporary or Permanent Changes

Standard VI Chemistry

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Column - I	Column - II
a. Large crystals	i. Turns lime water milky
b. Depositing a layer of zinc on iron	ii. Physical change
c. Souring of milk	iii. Rust
d. Carbon dioxide	iv. Carbon dioxide
e. Iron oxide	v. Chemical change
f. Dissolving common salt in water	vi. Galvanisation