Question

Match the list I with list II to give the correct IUPAC names and mark the appropriate choice.

Answer 1

Answer:-

(A) The longest chain is of 10 carbons and 2-Methylpropyl is attached on 5th carbon.

$C{H}_3(C{H}_2{)}_4-\underset{C{H}_2-CH(C{H}_3{)}_2}{\underset{|}{\stackrel{5}{C}}H-(C{H}_2{)}_3}\stackrel{1}{C}{H}_3$

Therefore the IUPAC name for the following is 5-(2-Methylpropyl)-decane $\to \left(iii\right)$

(B) The numbering will be from that side wherever the bond will be on lowest carbon apart from priority.

$\stackrel{1}{C}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv \stackrel{4}{C}-\stackrel{5}{C}{H}_3$

Therefore the IUPAC name for the following is pent-1-ene-3-yne $\to \left(i\right)$.

(C) As the double bone lie on lowest carbon, the numbering will start from that side. Since phenyl group is added on 4th carbon, therefore the correct IUPAC name for the following is 4-phenylbut-1-ene $\to \left(iv\right)$ (Refer Image)

(D) Since the two carbon atoms are double bonded, "di" will be added as a prefix and the numbering will start from the lowest one.
$\stackrel{7}{C}{H}_3-\stackrel{6}{C}H=\stackrel{5}{C}H-\underset{C_2{H}_5}{\underset{|}{\stackrel{4}{C}}H}-\stackrel{3}{C}{H}_2-\stackrel{2}{C}H=\stackrel{1}{C}{H}_2$

Therefore the correct IUPAC name for the following 4-ethyl-1,5-hepta-di-ene $\to \left(ii\right)$