Question

Match the number of nucleotides of genome of Column-I with the organisms of Column-II. Choose the correct option given below.

Column - I	Coloumn - II
1. 5386 nucleotides	p. E. coli
2. 48502 dp	q. Man
3. $4.6\times {10}^6$ bp	r. Drosophila
4. $3.3\times {10}^9$ bp	s. $\varphi \times$ 174 bacteriophage
	t. Bacteriophage lambda

• A. 1- r, 2- t, 3- s, 4- p
• B. 1- s, 2- p, 3- q, 4- r
• C. 1- s, 2- t, 3- p, 4- q
• D. 1- s, 2- q, 3- p, 4- t

Answer 1

Answer: (C)

1- s, 2- t, 3- p, 4- q

The genome of the $\varphi$ $X$ 174 bacteriophage whose genome was sequenced and there are 5386 nucleotides.

The genome of the bacteriophage lambda is 48502 bp.

The genome of the bacterium Escherichia coli contains 4.6 x 10${}^6$ bp.

The genome of man contains 3.3 x 10${}^9$ bp.

Thus, the correct answer is option C.