Question

Match the plots in column I with their orders in column II and mark the appropriate choice.

	Column II
(i)	Zero order
(ii)	First order
(iii)	Second order
(iv)	Third order

• A. $\left(A\right)\to \left(iii\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(i\right),\left(D\right)\to \left(iv\right)$
• B. $\left(A\right)\to \left(i\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(iii\right),\left(D\right)\to \left(iv\right)$
• C. $\left(A\right)\to \left(iv\right),\left(B\right)\to \left(iii\right),\left(C\right)\to \left(ii\right),\left(D\right)\to \left(i\right)$
• D. $\left(A\right)\to \left(ii\right),\left(B\right)\to \left(i\right),\left(C\right)\to \left(iii\right),\left(D\right)\to \left(iv\right)$

Answer 1

The correct option is B $\left(A\right)\to \left(i\right),\left(B\right)\to \left(ii\right),\left(C\right)\to \left(iii\right),\left(D\right)\to \left(iv\right)$

Relation between $t_{half}$ and $concentration$ is given by:-

$t_{1/2}\alpha \frac{1}{A^{n-1}}$

where $n-1$ is power of $A$ means $concentration$ and $n$ is order of reaction.

So the correct option is [B].