Question

Match the polymers given in Column I with the type of linkage present in them given in Column II.

	Column I		Column II
(i)	Terylene	(a)	Glycosidic linkage
(ii)	Nylon	(b)	Ester linkage
(iii)	Cellulose	(c)	Phosphodiester linkage
(iv)	Protein	(d)	Amide linkage
(v)	RNA

Answer 1

Correct match

	Column I		Column II
(i)	Terylene	(b)	Ester linkage
(ii)	Nylon	(d)	Amide linkage
(iii)	Cellulose	(a)	Glycosidic linkage
(iv)	Protein	(d)	Amide linkage
(v)	RNA	(c)	Phosphodiester linkage

Part (i):

Terylene has an ester linkage as it is formed when a carboxylic acid reacts with an alcohol to yield an ester with the release of a water molecule

(i)

Terylene

(b)

Ester Linkage

Part (ii):

Nylon 6,6 has an amide linkage as it is formed when hexamethylenediamine reacts with adipic acid. It releases a water molecule and forms an amide bond.

(ii)

Nylon

(d)

Amide linkage

Part (iii):

Cellulose is a polysaccharide in which glucose monomers are linked in unbranched chains by \(\beta\)-1,4-glycosidic linkage, i.e., it has an ethereal linkage \((-O-)\).

(iii)

Cellouse

(a)

Glycosidic linkage

Part (iv):

Proteins are polyamide polymers formed by linking the \(\alpha\)- carbonyl group of one amino acid to the \(\alpha\)- amine group of another amino acid with a peptide bond (also called an amide bond).

(iv)

Protein

(d)

Amide linkage

Part (v):

RNA forms phosphodiester linkage as the 3' carbon atom of one sugar molecule attaches with 5’ carbon of another, and hence gives the 3’,5’ phosphodiester linkage.

(v)

RNA

(c)