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Question

Match the polymers given in Column I with their commercial names given in Column II

Column I Column II
(i)

Polyester of glycol and phthalic acid

(a)

Novolac

(ii)

Copolymer of 1,3-butadiene and styrene

(b) Glyptal
(iii)

Phenol and formaldehyde resin

(c)

Buna-S

(iv)

Polyester of glycol and terephthalic acid

(d)

Buna-N

(v)

Copolymer of 1,3-butadiene and acrylonitrile

(e)

Dacron


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Solution

Part (i):

The polyester of ethylene glycol and phthalic acid is Glyptal.


(i)

Polyester of glycol and phthalic acid

(b) Glyptal

Part (ii):

The copolymer of 1,3-butadiene and styrene is Buna-S, a synthetic rubber.

(ii)

Copolymer of 1,3-butadiene and styrene

(c) Buna-S

Part (iii):

The condensation reaction between phenol and formaldehyde forms Novolac, which is a linear polymer used in paints.

(iii) Phenol and formaldehyde resin (a) Novolac


Part (iv):

The polyester of glycol and terephthalic acid is terylene or dacron. It is an example of a condensation polymer.


(iv)

Polyester of glycol and terephthalic acid

(e) Dacron

Part (v):

Buna-N, an artificial rubber, is obtained by the copolymerisation of 1,3-butadiene and acrylonitrile.


(v)

Copolymer of 1,3-butadiene and acrylonitrile

(d) Buna-N


Correct Match
Column I Column II
(i) Polyester of glycol and phtalic acid (d) Glyptal
(ii) Copolymer of 1,3-butadiene and styrene (c) Buna -S
(iii) Phenol and formaldehyde resin (a) Novolac
(iv) Polyester of glycol and terephtalic acid (e) Dacron
(v) Copolymer of 1,3-butadiene and acrylonitrile (d) Buna-N

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