Match the reactant in Column-I with the reaction in Column-II.
I II
(i) Acetic acid (a) Stephen
(ii) Sodium phenate (b) Friedel-Crafts
(iii) Methyl cyanide (c) HVZ
(iv) Toluene (d) Kolbe's

i - d, ii - b, iii - c, iv - a

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i - c, ii - d, iii - a, iv - b

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i - c, ii - a, iii - d, iv - b

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i - b, ii - c, iii - a, iv - d

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Solution

The correct option is B i - c, ii - d, iii - a, iv - b
The above reaction is an HVZ reaction. Reactant can also be acetic acid, i.e. $C H_{3} C O O H$

Stephen Reaction-

$R - C \equiv N Methyl cyanide S n C l_{2} / H C l - ------ \to R - C H O$

Kolbe's Electrolysis-
$2 C_{6} H_{5} O^{-} N a^{+} + 2 H_{2} O \to C_{6} H_{5} - C_{6} H_{5} + 2 C O_{2} + H_{2} + N a O H$
Toluene is used as a reactant in the Friedal-Crafts Reaction.
The correct match is -

$i - c, i i - d, i i i - a, i v - b$

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I	II
(i) Acetic acid	(a) Stephen
(ii) Sodium phenate	(b) Friedel-Crafts
(iii) Methyl cyanide	(c) HVZ
(iv) Toluene	(d) Kolbe's

Match the reactant in Column-I with the reaction in Column-II. I II (i) Acetic acid(a) Stephen(ii) Sodium phenate(b) Friedel-Crafts(iii) Methyl cyanide(c) HVZ(iv) Toluene(d) Kolbe's

Match the reactant in Column-I with the reaction in Column-II.
I II
(i) Acetic acid (a) Stephen
(ii) Sodium phenate (b) Friedel-Crafts
(iii) Methyl cyanide (c) HVZ
(iv) Toluene (d) Kolbe's