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Byju's Answer
Standard XII
Chemistry
Derivation of Kp and Kc
Match the rea...
Question
Match the reaction from List I with the ratio of value of equilibrium constant in List II.
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Solution
We know that,
K
P
=
K
C
(
R
T
)
△
n
;
△
n
=
No. of moles gaseous (products - reactants)
(A)
A
2
(
g
)
+
3
B
2
(
g
)
⇌
2
A
B
3
(
g
)
⇒
△
n
=
2
−
1
−
3
=
−
2
⇒
K
P
=
K
C
(
R
T
)
−
2
(B)
A
2
(
g
)
+
B
2
(
g
)
⇌
A
B
(
g
)
∴
△
n
=
2
−
1
−
1
=
0
⇒
K
P
=
K
C
(
R
T
)
0
=
K
C
(C)
A
(
s
)
+
3
/
2
B
2
(
g
)
⇌
A
B
3
(
g
)
∴
△
n
=
1
−
3
/
2
=
−
1
/
2
⇒
K
P
=
K
C
(
R
T
)
−
1
/
2
(D)
A
B
2
(
g
)
⇌
A
B
(
g
)
+
1
/
2
B
2
(
g
)
△
n
=
1
+
1
/
2
−
1
=
1
/
2
⇒
K
P
=
K
C
(
R
T
)
1
/
2
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