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Question

Match the reaction from List I with the ratio of value of equilibrium constant in List II.

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Solution

We know that, KP=KC(RT)n;n= No. of moles gaseous (products - reactants)
(A) A2(g)+3B2(g)2AB3(g)
n=213=2
KP=KC(RT)2
(B) A2(g)+B2(g)AB(g)
n=211=0
KP=KC(RT)0=KC
(C) A(s)+3/2B2(g)AB3(g)
n=13/2=1/2
KP=KC(RT)1/2
(D) AB2(g)AB(g)+1/2B2(g)
n=1+1/21=1/2
KP=KC(RT)1/2

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