Match the reactions with the reaction types- Veginarray -1- - WhineI- - 3 CuS -8 HNO -3 rightarrow 3 CuSO -4-8 NO g -4 H -2 O - A- Combination reaction 11 lhlineII- NH 3- HCl -rightarrow NH4 Cl - B- Displacement reaction WIhlineIII- Br-2-2 KI -rightarrow 2 KBr - I -2 - C- Double displacement reaction lllhlinelendarray A- I-A- II-D- III-B- IV-CB- I-D- II-B- III-A- IV-CC- I-D- II-A- III-B- IV-CD- I-D- II-A- III-C- IV-B

The correct option is C I D, II A, III B, IV C3CuS + 8HNO_3→ 8NO(g) + 4H_2O: CuS is getting oxidized and HNO_3 is getting reduced. Hence it is an oxidation red ...

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Byju's Answer

Standard IX

Chemistry

Double Displacement Reaction

Match the rea...

Question

Match the reactions with the reaction types:
$\begin{matrix} I . 3 C u S + 8 H N O_{3} \to 3 C u S O_{4} + 8 N O (g) + 4 H_{2} O & A . C o m b i n a t i o n r e a c t i o n I I . N H_{3} + H C l \to N H_{4} C l & B . D i s p l a c e m e n t r e a c t i o n I I I . B r_{2} + 2 K I \to 2 K B r + I_{2} & C . D o u b l e d i s p l a c e m e n t r e a c t i o n I V . N a_{2} S + 2 H C l \to 2 N a C l + H_{2} S & D . O x i d a t i o n - r e d u c t i o n r e a c t i o n \end{matrix}$

I-A, II-D, III-B, IV-C

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I-D, II-B, III-A, IV-C

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I-D, II-A, III-B, IV-C

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I-D, II-A, III-C, IV-B

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Solution

The correct option is C I-D, II-A, III-B, IV-C
$3 C u S + 8 H N O_{3} \to 8 N O (g) + 4 H_{2} O$ : CuS is getting oxidized and $H N O_{3}$ is getting reduced. Hence it is an oxidation-reduction reaction.

$N H_{3} + H C l \to N H_{4} C l$ : two reactants combine to form one product: combination reaction.

$B r_{2} + 2 K I \to 2 K B r + I_{2}$ : Bromine displaces iodine from potassium iodide, hence it is a displacement reaction.

$N a_{2} S + 2 H C l \to 2 N a C l + H_{2} S$ : it is a double displacement reaction, as their is an exchange of ions between $N a_{2} S$ and $H C l$

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Match the reactions with the reaction types: I. 3CuS+8HNO3→3CuSO4+8NO(g)+4H2OA. Combination reactionII. NH3+HCl→NH4ClB. Displacement reactionIII. Br2+2KI→2KBr+I2C. Double displacement reactionIV. Na2S+2HCl→2NaCl+H2SD. Oxidation−reduction reaction