Question

Match the reagent in List-1 with respective observation in List-2.

Answer 1

(a)$\begin{array}{ccccc}F{e}^{3+}& +& 3\left[Fe\right(CN{)}_6{]}^{4-}& ⟶& \stackrel{III}{F{e}_4}\stackrel{II}{\left[Fe\right(CN{)}_6{]}_3\downarrow }\\ & & & & Blueppt.\\ & & & & \left(Prussianblue\right)\end{array}$
$\begin{array}{cccccc}3Z{n}^{2+}& +& 2K_4\left[Fe\right(CN{)}_6]& ⟶& K_{2}Z{n}_3\left[Fe\right(CN{)}_6{]}_2\downarrow & +6K^{+}\\ & & & & \left(white\right)& \end{array}$
$\begin{array}{ccccc}C{u}^{2+}& +& K_4\left[Fe\right(CN{)}_6]& ⟶& C{u}_2\left[Fe\right(CN{)}_6]\downarrow \\ & & & & \left(Chocolatebrown\right)\end{array}$
(b)$\begin{array}{cccccc}(N{H}_4{)}_2& +& ZnS{O}_4\&⟶& ZnS\downarrow & +& (N{H}_4{)}_{2}S{O}_4\\ & & & & & \left(White\right)\end{array}$
(c)$\begin{array}{ccccccc}C{u}^{2+}& +& 2N{H}_{4}OH& ⟶& Cu(OH{)}_2\downarrow & +& 2N{H}_4^{+}\\ & & & & \left(Blue\right)& & \\ & & & & \downarrow & ExcessofN{H}_{3}solution& \\ & & & & \left[Cu\right(N{H}_3{)}_4{]}^{2+}& & \\ & & & & Deepbluesolution& & \end{array}$