Question

Match the species given in column $I$ with the properties mentioned in column $II$

$\begin{array}{cccc}& \text{Column I}& & \text{Column II}\\ \left(A\right)& \text{Diborane}& \left(i\right)& \text{used as a flux for soldering metals}\\ \left(B\right)& \text{Gallium}& \left(ii\right)& \text{crystalline form of silica}\\ \left(C\right)& \text{Borax}& \left(iii\right)& \text{banana bond}\\ \left(D\right)& \text{Aluminosilicate}& \left(iv\right)& \text{low melting high boiling useful for measuring high temperatures}\\ \left(E\right)& \text{Quartz}& \left(v\right)& \text{used as a catalyst in petrochemical industries.}\end{array}$

Answer 1

$\text{Analyzing the options}$

(A) Diborane, $B_2{H}_6$ has two banana bonds i.e. $3$ center-$2$ electrons bond.

(B) Gallium has a low melting point and higher boiling point and hence it is used as a liquid at various ranges of temperature for measuring high temperature in thermometers.

(C) Borax is a white crystalline solid. It is used as a flux for soldering metals

(D) Aluminosilicate is a compound which is formed when in $Si{O}_2$ structure some of the $Si$ atoms are replaced by $A{l}^{3+}$ generating negative charge on structure, overall charge is balanced by $N{a}^{+}$ or $K^{+}$ counter ions. These aluminosilicates are used as catalyst in petrochemical industries for cracking of hydrocarbons and isomerization.

(E) Quartz is the crystalline forms of Silica.

Hence, the correct match will be given as -

$\begin{array}{cccc}& \text{Column I}& & \text{Column II}\\ \left(A\right)& \text{Diborane}& \left(iii\right)& \text{banana bond}\\ \left(B\right)& \text{Gallium}& \left(iv\right)& \text{low melting high boiling useful for measuring high temperatures}\\ \left(C\right)& \text{Borax}& \left(i\right)& \text{used as a flux for soldering metals}\\ \left(D\right)& \text{Aluminosilicate}& \left(v\right)& \text{used as a catalyst in petrochemical industries.}\\ \left(E\right)& \text{Quartz}& \left(ii\right)& \text{crystalline form of silica}\end{array}$