Match the species im Column I with the bond order in Column II.
Column I | Column II | ||
A | \(NO\) | \((i)\) | 1.5 |
B | \(CO\) | \((ii)\) | 2.0 |
C | \(O_2^-\) | \((iii)\) | 2.5 |
D | \(O_2\) | \((iv)\) | 3.0 |
\(NO~\text{total electrons}=15\)
\(CO~\text{total electrons}=14\)
\(O_2^-~\text{total electrons}=17\)
\(O_2~\text{total electrons}=16\)
Calculation of bond order
Electroni configuration of \(NO\) molecule is:
\(\sigma 1s^2\sigma^\ast 1s^2\sigma 2s^2\sigma^{\ast}2s^2\pi2p_x^2=\pi 2p_y^2\sigma 2p_z^2\)
\(\pi^\ast2p_x^1=\pi^\ast 2p_y^0\)
Bond order of \(NO=\left [ \dfrac{10-5}{2} \right ]=2.5\)
Electronic configuration of \(CO\) molecule is:
\(\sigma 1s^2\sigma^\ast 1s^2\sigma 2s^2\sigma^{\ast}2s^2\pi2p_x^2=\pi 2p_y^2\sigma 2p_z^2\)
Bond order \(CO=\left [ \dfrac{10-4}{2} \right ]=3\)
Electronic configuration of \(O_2\) molecule is:
\(\sigma 1s^2\sigma^\ast 1s^2\sigma 2s^2\sigma^{\ast}2s^2\sigma 2p_z^2\pi2p_x^2=\pi 2p_y^2\)
\(\pi^\ast 2p_x^1=\pi^{\ast}P_y^1\)
Bond order of \(O_2=\left [ \dfrac{10-6}{2} \right ]=2\)
Electronic configuration of \(O_2^-\) is:
\(\sigma 1s^2\sigma^\ast 1s^2\sigma 2s^2\sigma^{\ast}2s^2\sigma 2p_z^2\pi2p_x^2=\pi 2p_y^2\)
\(\pi^\ast 2p_x^2=\pi^{\ast}P_y^1\)
Bond Order of \(O_2^-=\left [ \dfrac{10-7}{2} \right ]=1.5\)
Column I | Column IUI | ||
A | \(NO\) | \((iii)\) | 2.5 |
B | \(CO\) | \((iv)\) | 3 |
C | \(O_2^-\) | \((i)\) | 1.5 |
D | \(O_2\) | \((ii)\) | 2 |