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Byju's Answer
Standard XII
Chemistry
VSEPR Theory
Match the spe...
Question
Match the species in in
C
o
l
u
m
n
I
with their corresponding properties in
C
o
l
u
m
n
I
I
Open in App
Solution
A)
X
e
O
3
H
y
b
r
i
d
i
z
a
t
i
o
n
=
N
u
m
b
e
r
o
f
σ
b
o
n
d
s
+
l
o
n
e
p
a
i
r
o
n
c
e
n
t
r
a
l
a
t
o
m
=
3
+
1
=
4
=
s
p
3
s
p
3
with one lone pair, so shape is Pyramidal Triagonal
X
e
F
6
+
3
H
2
O
→
X
e
O
3
+
6
H
F
B)
X
e
O
F
4
H
y
b
r
i
d
i
z
a
t
i
o
n
=
5
σ
b
o
n
d
s
+
1
l
o
n
e
p
a
i
r
o
n
c
e
n
t
r
a
l
a
t
o
m
=
6
=
s
p
3
d
2
s
p
3
d
2
with one lone pair, so shape is Square Pyramidal structure.
X
e
F
6
+
H
2
O
→
X
e
O
F
4
+
2
H
F
C)
X
e
O
2
F
4
H
y
b
r
i
d
i
z
a
t
i
o
n
=
6
σ
b
o
n
d
s
+
2
l
o
n
e
p
a
i
r
o
n
c
e
n
t
r
a
l
a
t
o
m
=
6
=
s
p
3
d
2
D)
X
e
O
3
F
2
H
y
b
r
i
d
i
z
a
t
i
o
n
=
s
p
3
It has tetrahedral shape.
E)
X
e
O
4
It has triagonal bi pyramidal shape.
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