Question

Match the species (in List I) with Bond-order (in List II).

Answer 1

1. ${NO}^{+}=\frac{10-4}{2}=3$
2. $NO=\frac{10-5}{2}=2.5$
3. ${NO}^{-}=\frac{10-6}{2}=2$
   ${NO}^{+}$ has a Bond order of $3$
   $NO$ has a Bond order of $2.5$
   ${NO}^{-}$ has a Bond order of $2$
   Bond order=$\frac{No.ofBondingelectrons-No.ofAntiBondingelectrons}{2}$