Question

Match the species (in List I) with the bond order (in List II).

Answer 1

Bond order:
$N_2-3.0,N\equiv N$
$O_2-2.0,O=O$
$F_2-1.0,F-F$
$O_2^{+}-2.5,B.O=\frac{(N_b-N_a)}{2}$
$=\frac{(10-5)}{2}=2.5$