ENDEANOELENDEA:
Number of ways =5
Total number of permutation =5! Ways
A⟶1
E fixed in first and last places
Therefore number of ways
=7!2!=2!×5!B⟶4
D,L,N are not in last 5 positions
Therefore number of permutations
=4!2!×5!3!=2×5!
In which they occur
=9×5!=2×5!=7×5!
C⟶3
The number of permutations in which the letter A,E,O occur in odd positions only.
Total numbers of odd positions =5
Permutation of AEEEO are 5!3!
Total numbers of even positions =4
Permutation =4!2!
Total permutations4!2!×5!3!=2×5!
D⟶2