wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match the Statements / Expressions in List 1 with the Statements / Expressions in List 2 and indicate your answer by darkening the appropriate bubbles in the 4×4 matrix given in the ORS.

Open in App
Solution

(A)y=x2+2x+4x+2
x2+(2y)x+42y=0
y2+4y120
y6 or y2
minimum value is 2.
(B) (A+B)(AB)=(AB)(A+B)
AB=BA
as A is symmetric and B is skew symmetric
(AB)t=AB
k=1 and k=3
(C) a=log3log323a=log23
Now 1<2k+log32<2
1<3.2k<2
log2(32)<k<log2(3)
k=1 or k<2 and k<3
(D) sinθ=cosϕcos(π2θ)=cosϕ
π2θ=2nπ±ϕ
1π(θ±ϕπ2)=2n
0 and 2 are possible.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Inverse of a Function
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon