Equation of Tangent at a Point (x,y) in Terms of f'(x)
Match the sta...
Question
Match the statements/expressions in List 1 with the values given in List 2.
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Solution
A) x.esinx−cosx=0
⇒esinx=cosxx Let f(x)=cosxx,g(x)=esinx Then from figure, number of solutions is 1. B) ∣∣
∣∣k414k2221∣∣
∣∣=0⇒k=2,4 C) |x−1|+|x−2|+|x+1|+|x+2|=4k From figure 2 we have k=2,3,4,5, so number of solution is 4 D) dydx=y+1⇒∫dyy+1=∫dx⇒ln(y+1)=x+c ⇒y+1=e(x+c)⇒y=e(x+c)−1 For x=0,y=1⇒1=ec−1⇒ec=2 y=e(x+ln2)−1 And for x=ln2 y=e2ln2−1=3