wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Match the statements/expressions in List 1 with the values given in List 2.

Open in App
Solution

A) x.esinxcosx=0
esinx=cosxx
Let f(x)=cosxx,g(x)=esinx
Then from figure, number of solutions is 1.
B) ∣ ∣k414k2221∣ ∣=0k=2,4
C) |x1|+|x2|+|x+1|+|x+2|=4k
From figure 2 we have k=2,3,4,5, so number of solution is 4
D) dydx=y+1dyy+1=dxln(y+1)=x+c
y+1=e(x+c)y=e(x+c)1
For x=0,y=11=ec1ec=2
y=e(x+ln2)1
And for x=ln2
y=e2ln21=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometrical Interpretation of a Derivative
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon