Question

Match the statements in Column I with suitable statements in Column II.
$\begin{array}{cccc}& \text{Column I}& & \text{Column II}\\ \text{a.}& \text{A gas in contact with an}& \text{p.}& \text{Electrode potential}\\ & \text{inert electrode}& & \\ \text{b.}& \text{The potential difference in}& \text{q.}& O_2\text{at anode metal and}\\ & \text{volts between the two}& & \text{the solution of metal ion}\\ & \text{electrodes}& & \\ \text{c.}& Li\text{metal has the lowest}& \text{r.}& H_2\left(g\right)/Pt\text{potential}\\ & \text{standard electrode}& & \\ & \text{potential}& & \\ \text{d.}& \text{Electrolysis of aq.}N{a}_{2}S{O}_4& \text{s.}& \text{Strongest reducing agent}\\ & \text{using}Pt\text{electrodes}& & \\ & & \text{t.}& -3.06\text{Volt}\end{array}$

• A. (a – r; b – p; c – s; d – q)
• B. (a – r; b – s; c – t; d – q)
• C. (a – p; b – r; c – s; d – q)
• D. (a – r; b – p; c – q; d – s)

Answer 1

The correct option is A (a – r; b – p; c – s; d – q)

1. $H_2\left(g\right)/Pt$ is an example of a gas in contact with an inert electrode.
2. The potential difference between the two electrodes is called the electrode potential.
3. $Li$ has the lowest standard electrode potential and hence, the lowest tendency to get reduced. It acts the strongest reducing reagent.
4. Electrolysis of aq $N{a}_{2}S{O}_4$ produces $O_2$ at the anode

$2H_{2}O\to O_2+4H^{+}+4e^{-}$