Match the statements in column-I with the statements in column-II:
Column-I
Column-II
(A)
A tight string is
(P)
At the middle, antinode is formed fixed at both ends in odd harmonic and sustaining standing wave
(B)
A tight string is
(Q)
At the middle,node fixed at one end is formed in even and free at ond harmonic and free at the other end
(C)
Standing wave is
(R)
At the middle, neither formed in an open node nor antinode is organ pipe. End correction formed is not negligible
(D)
Standing wave is
(S)
Phase difference formed in a closed between SHM's of organ pipe. End any two particles correction is not will be either or negligible zero.
Which of the following option has the correct combination considering column-I and Column-II.
| Column-I | Column-II | ||
| (A) | A tight string is | (P) | At the middle, antinode is formed fixed at both ends in odd harmonic and sustaining standing wave |
| (B) | A tight string is | (Q) | At the middle,node fixed at one end is formed in even and free at ond harmonic and free at the other end |
| (C) | Standing wave is | (R) | At the middle, neither formed in an open node nor antinode is organ pipe. End correction formed is not negligible |
| (D) | Standing wave is | (S) | Phase difference formed in a closed between SHM's of organ pipe. End any two particles correction is not will be either or negligible zero. |
The correct option is B D → R, S
(A) Number of loops (of length λ/2) will be even or odd and node or antinode will respectively be formed at the middle.
Phase difference between two particle in same loop will be zero and that between two particles in adjacent loops will be .
(B) and (D) Number of loops will both be integral. Hence neither a node nor and antinode will be formed in the middle.
Phase difference between two particle in same loop will be zero and that between two particles in adjacent loops will be π
(C) Numberof loops (of length λ2) will be even or odd and antinode or node will respectively be formed at the middle.
Phase difference between two particles in same loop will be zero and that between two particles in adjacentm loopswill be π
Hence option (D) is correct
(A) Number of loops (of length λ/2) will be even or odd and node or antinode will respectively be formed at the middle.
Phase difference between two particle in same loop will be zero and that between two particles in adjacent loops will be .
(B) and (D) Number of loops will both be integral. Hence neither a node nor and antinode will be formed in the middle.
Phase difference between two particle in same loop will be zero and that between two particles in adjacent loops will be π
(C) Numberof loops (of length λ2) will be even or odd and antinode or node will respectively be formed at the middle.
Phase difference between two particles in same loop will be zero and that between two particles in adjacentm loopswill be π
Hence option (D) is correct
