Question

Match the terms given in Column I with the expressions given in Column II.

	Column I		Column II
A	Mass Percentage	$\left(i\right)$	$\frac{\text{Number of moles of the solute component}}{\text{Volume of solution in Litre}}$
B	Volume Percentage	$\left(ii\right)$	$\frac{\text{Number of moles of component}}{\text{Total number of moles of components}}$
C	Mole Fraction	$\left(iii\right)$	$\frac{\text{Volume of the solute component in solution}}{\text{Total Volume of solution}}\times 100$
D	Molality	$\left(iv\right)$	$\frac{\text{Mass of the solute component in solution}}{\text{Total mass of the solution}}\times 100$
E	Molarity	$\left(v\right)$	$\frac{\text{Number of moles of the solute components}}{\text{Mass of solvent in kilograms}}$

Answer 1

Part (A)

Mass percentage: The amount of solute $\left(g\right)\text{present in}100g$ of the solution.

$\text{Mass Percentage}=\frac{\text{Mas of solute}\left(g\right)}{\text{Mass of solution}\left(g\right)}\times 100$

$\left(A\right)\to \left(i\right)$

Part (B)

Volume percentage: The amount of solute $\left(\text{in}mL\right)\text{present in}100mL$ of the solution.

$\text{Volume percentage}=\frac{\left(\text{Volume of Solute}\right(mL\left)\right)}{\left(\text{Volume of Solution}\right(mL\left)\right)}\times 100$

$\left(B\right)\to \left(iii\right)$

Part (C)

Mole fraction represents the number of moles of a particular component in a mixture divided by the total number of moles in the given mixture. mole fraction can be represented by ${}^{\prime }{X}^{\prime }$.

$\text{Mole Fraction of Component}=\frac{\left(\text{Number of moles of given component}\right)}{\left(\text{Total number of moles in solution}\right)}$

$\left(C\right)\to \left(ii\right)$

Part (D)

Molality of a solution is defined as the number of moles of solute dissolved per $1000g$ of the solvent.

$\text{Molality}=\frac{\left(\text{Number of moles of solute}\right)}{\text{(Mass of solvent in kg})}$

$\left(D\right)\to \left(v\right)$

Part (E)

Molarity: The number of moles of solute dissolved per litre of the solution is called the molarity of the solution. Molarity actually represents the concentration of the solution in $mol{L}^{-1}$

$\text{Molarity}=\frac{\left(\text{Number of moles of solute}\right)}{\left(\text{Volume of solution in Liters}\right)}$

$\left(E\right)\to \left(i\right)$