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Question

Match the thermodynamic processes given below:

Column IColumn IIA. Freezing of water at 273K and 1 atmp. q=0B. Expansion of 1 mole of an ideal gas into a vacuum under isolated conditions q. W=0C. Mixing of equal volumes of two ideal gases at constant temperature and pressure in an isolated containerr. ΔSsys<0D. Reversible heating of H2(g) at 1 atm from 300 K to 600K, followed by reversible cooling to 300K at 1 atms. ΔU=0t. ΔG=0


A

(A) r, t; (B) q, s, t; (C) p, q, s; (D) p, q, s

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B

(A) r, t; (B) p, q, s; (C) p, q, s; (D) q, s, t

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C

(A); q, s, t(B) p, q, s; (C) p, q, s; (D) r, t

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D

(A) r, t; (B) p, q, s; (C) p, q, s; (D) q, s, t

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Solution

The correct option is B

(A) r, t; (B) p, q, s; (C) p, q, s; (D) q, s, t


(A) r, t; (B) p, q, s; (C) p, q, s; (D) q, s, t
(A) H2O(l) H2O(s))
Q < 0, W < 0 (expansion)
ΔU=0
Ti=Tf, ΔG=0 ΔSsys<0 (solid state is more ordered than liquid state)
ΔU<0; ΔG=0 (At equilibrium)
(B) q = 0 (isolated), W = 0 (Pext=0)
ΔSsys>0 V2>V1
ΔU=0 q=W=0
ΔG<0 p2<p1
(C) q = 0 (isothermal mixing of ideal gases at constant p)
W=0 ΔU=0; q=0, ΔSsys>0
V2>V1, ΔU=0
ΔT=0
ΔG<0 mixing is spontaneous.
(D) q = 0 (returning to same state and by same path)
W = 0
ΔSsys=0 (same initial and final states)
ΔU=0
Ti=Tf, ΔG=0


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