Question

Match the titration graphs
(1) NaOH + $N{H}_4$OH vs HCl
(2) $C{H}_3$ COOH vs NaOH
(3)HCl vs NaOH
(4)$C{H}_3$ COOH vs $N{H}_4$OH
a)

b)

c)

d)

• A. 1-(c) 2-(a) 3-(d) 4-(b)
• B. 1-(b) 2-(c) 3-(d) 4-(a)
• C. 1-(c) 2-(b) 3-(a) 4-(d)
• D. 1-(b) 2-(a) 3-(d) 4-(c)

Answer 1

The correct option is B 1-(b) 2-(c) 3-(d) 4-(a)

(NaOH + NH4OH) vs HCl:
As there is mixture of strong acid and weak base. Neutralisation happens in two steps. So the curve gets two breaks.

(ii) $C{H}_3$ COOH vs $N{H}_4$OH
(weak acid vs weak base)

(iii) HCl vs NaOH
(strong acid vs strong base)
For the titration of stong acid vs strong base at first the conductance decrease then it increases.

(iv) $C{H}_3$ COOH vs NaOH
Weak acid vs strong base

Before addition of NaOH, the solution shows poor conductance due to low ionization of $C{H}_3$COOH after addition of NaOH, $C{H}_3$COOH is replaced by $C{H}_3$COONa which is very strong conducting.