Match the two columns- beginarray 11Column-I - Column-II A Abscissa - p x B Ordinate - q y y C Co-ordinate - r - x - y 1D Origin -s 0 e n d a r r a y Choose the correct option-A- A - p - B - q - C - s - D - rB- A - r - B - p - C - q - D - sC- A - p - B - q - C - r - D - sD- A - s - B - p - C - r - D - q

The correct option is C (A) → p; (B) → q; (C) → r; (D) → s (A) → p; (B) → q; (C) → r; (D) → s ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Locating a Point in Cartesian Plane

Match the two...

Question

Match the two columns.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) A b s c i s s a & (p) x (B) O r d i n a t e & (q) y (C) C o - o r d i n a t e & (r) x, y (D) O r i g i n & (s) 0 \end{matrix}$
Choose the correct option:

$(A) \to p; (B) \to q; (C) \to s; (D) \to r$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(A) \to r; (B) \to p; (C) \to q; (D) \to s$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(A) \to s; (B) \to p; (C) \to r; (D) \to q$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

Suggest Corrections

Similar questions

Read the figure. On the basis of this figure match the Column-I with Column-II.

$\begin{matrix} Column-I & Column-II (A) Co-ordinates of point C is & (p) - 5 (B) The abscissa of point E is & (q) (0, 0) (C) The ordinate of the point F is & (r) 0 (D) Co-ordinates of point O is & (s) (- 5, 3) \end{matrix}$
Choose the correct option:

Match the two columns :
$\begin{matrix} C o l u m n - I & C o l u m n - I I A) Sum of all the angles & P) Right anlges of a quadrilateral is B) In a ∥ gm, the angle & Q) Rectangle bisectors of two adjacent angles intersect at C) Angle bisectors of form & R) 45^{\circ} a ∥ gm from a D) The diagonals of a & S) 4 right angles square are equal and bisect each other at an angle of \end{matrix}$
Choose the correct option:

\begin{matrix} Column -I & Column -II (a) N H_{4} C l & (P) Hydrogen bond (b) C u S O_{4} .5 H_{2} O & (Q) Co-ordinate bond (c) H N C & (R) Ionic bond (d) L i q u i d H_{2} O_{2} & (S) Covalent bond \end{matrix}

Q. Match Column – I with Column – II

\begin{matrix} Column - I & Column - II a) [(P h_{3} P)_{3} R h C l] & p) Zeigler -Natta Catalyst b) T i C l_{4} + (C_{2} H_{5})_{3} A l & q) Anti - knocking agent c) (C_{2} H_{5})_{4} P b & r) Cisplatin d) [P t C l_{2} (N H_{3})_{2}] & s) Wilkinson's catalyst \end{matrix}

Q. Match the following by appropriately matching the lists based on the information given in

Column I

and

Column II

\begin{matrix} C o l u m n I & C o l u m n I I (T y p e o f △ A B C) a. cot \frac{A}{2} = \frac{b + c}{a} & p. always right angled b. a tan A + b tan B = (a + b) tan \frac{A + B}{2} & q. always isosceles c. a cos A = b cos B & r. may be right angled d. cos A = \frac{sin B}{2 sin C} & s. may be right angled isosceles \end{matrix}

Join BYJU'S Learning Program

Match the two columns. Column−IColumn−II(A) Abscissa(p) x(B) Ordinate(q) y(C) Co−ordinate(r) x,y(D) Origin(s) 0 Choose the correct option:

The correct option is B (A)→p;(B)→q;(C)→r;(D)→s (A)→p;(B)→q;(C)→r;(D)→s

Match the two columns.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) A b s c i s s a & (p) x (B) O r d i n a t e & (q) y (C) C o - o r d i n a t e & (r) x, y (D) O r i g i n & (s) 0 \end{matrix}$
Choose the correct option:

The correct option is B
$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

$(A) \to p; (B) \to q; (C) \to r; (D) \to s$