Match the two columns- beginarray 11Column-I - Column-II A Abscissa - p x B Ordinate - q y y C Co-ordinate - r - x - y 1D Origin -s 0 e n d a r r a y Choose the correct option-A- A - p - B - q - C - s - D - rB- A - r - B - p - C - q - D - sC- A - p - B - q - C - r - D - sD- A - s - B - p - C - r - D - q

The correct option is C (A) → p; (B) → q; (C) → r; (D) → s (A) → p; (B) → q; (C) → r; (D) → s ...

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Byju's Answer

Standard IX

Mathematics

Locating a Point in Cartesian Plane

Match the two...

Question

Match the two columns.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) A b s c i s s a & (p) x (B) O r d i n a t e & (q) y (C) C o - o r d i n a t e & (r) x, y (D) O r i g i n & (s) 0 \end{matrix}$
Choose the correct option:

$(A) \to p; (B) \to q; (C) \to s; (D) \to r$

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$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

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$(A) \to r; (B) \to p; (C) \to q; (D) \to s$

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$(A) \to s; (B) \to p; (C) \to r; (D) \to q$

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Solution

The correct option is B
$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

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\begin{matrix} C o l u m n I & C o l u m n I I (T y p e o f △ A B C) a. cot \frac{A}{2} = \frac{b + c}{a} & p. always right angled b. a tan A + b tan B = (a + b) tan \frac{A + B}{2} & q. always isosceles c. a cos A = b cos B & r. may be right angled d. cos A = \frac{sin B}{2 sin C} & s. may be right angled isosceles \end{matrix}

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Match the two columns. Column−IColumn−II(A) Abscissa(p) x(B) Ordinate(q) y(C) Co−ordinate(r) x,y(D) Origin(s) 0 Choose the correct option:

The correct option is B (A)→p;(B)→q;(C)→r;(D)→s (A)→p;(B)→q;(C)→r;(D)→s

Match the two columns.
$\begin{matrix} C o l u m n - I & C o l u m n - I I (A) A b s c i s s a & (p) x (B) O r d i n a t e & (q) y (C) C o - o r d i n a t e & (r) x, y (D) O r i g i n & (s) 0 \end{matrix}$
Choose the correct option:

The correct option is B
$(A) \to p; (B) \to q; (C) \to r; (D) \to s$

$(A) \to p; (B) \to q; (C) \to r; (D) \to s$