Question

Match the two columns. Column II gives the degree of polynomials given in column I match them correctly –

Column 1	Column 2
$2–y^2–y^3+2y^8$	$2$
$2$	$1$
$5x-\sqrt{7}$	$0$
$4–x^2$	$8$

Answer 1

Matching the polynomials in Column-I to their respective degree in Column II:

Explanation for (A):

In (A) given polynomial is $2–y^2–y^3+2y^8$

Now the degree of a polynomial is equal to the highest degree of its variables.

The highest degree of a variable of polynomial $2–y^2–y^3+2y^8$ is $8$

Since $2y^8$ has the highest degree in the polynomial.

Hence, (A) matches with (IV).

Explanation for (B):

In (B) given polynomial is $2$

Now the degree of a polynomial is equal to the highest degree of its variables.

The highest degree of a variable of polynomial $2$ is $0$

Since $2=2\times 1=2\times y^0$ has the highest degree in the polynomial.

Hence, (B) matches with (III).

Explanation for (C):

In (C) given polynomial is $5x-\sqrt{7}$

Now the degree of a polynomial is equal to the highest degree of its variables.

The highest degree of a variable of polynomial $5x-\sqrt{7}$ is $1$

Since $5x=5x^1$ has the highest degree in the polynomial.

Hence, (C) matches with (II).

Explanation for (D):

In (D) given polynomial is $4–x^2$

Now the degree of a polynomial is equal to the highest degree of its variables.

The highest degree of a variable of polynomial $4–x^2$ is $2$

Since $x^2$ has the highest degree in the polynomial.

Hence, (D) matches with (I).

Column-I	Column-II
(A) $2–y^2–y^3+2y^8$	(IV) $8$
(B) $2$	(III) $0$
(C) $5x-\sqrt{7}$	(II) $1$
(D) $4–x^2$	(I) $2$