Match the value of the expression $x^{99} + x^{100} + x$ for the given values of $x$ .

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Solution

Let us calculate the value of the expression $x^{99} + x^{100} + x$ for given values of x:

For x = 1,
$x^{99} + x^{100} + x = 1^{99} + 1^{100} + 1 = 1 + 1 + 1 = 3$

For x = -1,
$x^{99} + x^{100} + x = (- 1)^{99} + (- 1)^{100} + (- 1) = - 1 + 1 + - 1 = - 1$

For x = 0,
$x^{99} + x^{100} + x = 0^{99} + 0^{100} + 0 = 0 + 0 + 0 = 0$

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Similar questions

x^{99} + x^{100} + x

x

x^{50}

(1 + x)^{100} + 2 x (1 + x)^{99} + 3 x^{2} (1 + x)^{98} + . . . . . . . . . + 101. x^{100}

lim x \to \infty \frac{{(x + 1)}^{100} + {(x + 2)}^{100} + . . + {(x + 50)}^{100}}{x^{100} + x^{99} + . . + x + 1} =

f (x) = \frac{x^{100}}{100} + \frac{x^{99}}{99} + . . . . . . . . . . . + \frac{x^{2}}{2} + x + 1

f^{'} (1) =

x > 0

\frac{x^{100}}{1 + x + x^{2} + x^{3} + . . . . + x^{200}}

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