Match the values of column II with column I and mark the appropriate choice-Column IColumn IIAMass of electroni 1-673- 10-27 kgBMass of protonii -1-602- 10-19 CCCharge of electroniii 9-1- 10-31KgDe-m for an electroniv 1-76- 108C-g

The correct option is B (A)→(iii), (B) → (i), (C)→ (ii), (D)→(iv) (A) Mass of electron = 9.1 × 10^ #8722;31Kg (B) Mass of proton = 1.673 × 10^ ...

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Byju's Answer

Standard XII

Chemistry

Introduction to Atomic Structure

Match the val...

Question

Match the values of column II with column I and mark the appropriate choice.
Column I Column II
(A) Mass of electron (i) $1.673 \times 10^{- 27}$ kg
(B) Mass of proton (ii) $- 1.602 \times 10^{- 19}$ C
(C) Charge of electron (iii) $9.1 \times 10^{- 31}$ Kg
(D) e/m for an electron (iv) $1.76 \times 10^{8}$ C/g

(A) \to (i), (B) \to (i i), (C) \to (i v), (D) \to (i i i)

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(A) \to (i i i), (B) \to (i), (C) \to (i i), (D) \to (i v)

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(A) \to (i i), (B) \to (i i i), (C) \to (i v), (D) \to (i)

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(A) \to (i), (B) \to (i i i), (C) \to (i i), (D) \to (i v)

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Solution

The correct option is B $(A) \to (i i i), (B) \to (i), (C) \to (i i), (D) \to (i v)$
(A) Mass of electron $= 9.1 \times 10^{- 31} K g$
(B) Mass of proton $= 1.673 \times 10^{- 27} k g$
(C) Charge of electron $= - 1.602 \times 10^{- 19} C$
(D) e/m for an electron $= 1.76 \times 10^{8} C / g$
Thus option B is the correct answer.

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	Column I		Column II
(A)	Mass of electron	(i)	$1.673 \times 10^{- 27}$ kg
(B)	Mass of proton	(ii)	$- 1.602 \times 10^{- 19}$ C
(C)	Charge of electron	(iii)	$9.1 \times 10^{- 31}$ Kg
(D)	e/m for an electron	(iv)	$1.76 \times 10^{8}$ C/g

Match the values of column II with column I and mark the appropriate choice.Column IColumn II(A)Mass of electron(i)1.673×10−27 kg(B)Mass of proton(ii)−1.602×10−19 C(C)Charge of electron(iii)9.1×10−31Kg(D)e/m for an electron(iv)1.76×108C/g

The correct option is B (A)→(iii),(B)→(i),(C)→(ii),(D)→(iv)(A) Mass of electron=9.1×10−31Kg(B) Mass of proton=1.673×10−27kg(C) Charge of electron=−1.602×10−19C(D) e/m for an electron=1.76×108C/gThus option B is the correct answer.