Question

Match the zeroes of the respective polynomials.

• A. $0$
• B. $\frac{3}{2}$
• C. $1$

Answer 1

$\text{I.}p\left(x\right)=2x-3$

We have to equalise the polynomials to zero to get zeroes.
$2x-3=02x=3x=\frac{2}{3}$

$\therefore$ zero of $p\left(x\right)=2x-3$ is $\frac{2}{3}$

$\text{II.}p\left(x\right)=\frac{x}{2}$

Similarly, $\frac{x}{2}=0x=0$
$\therefore$ Zero is $0$

$\text{III.}p\left(x\right)=1-x$

Similarly, $1-x=0x=1$

$\therefore$ Zero is $1$