Match using the given equation $Z n + C u S O_{4} - > C u + Z n S O_{4}$

Redox reaction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Cu in

C u S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Zn is getting oxidised as there is an increase in oxidation state from 0 to +2. So it is a reducing agent. Substance which gets reduced is called an oxidising agent and here it is Cu where it shows a decrease in oxidation number from +2 to 0. As this reaction involves both oxidation and reduction reaction it is called a redox reaction

Suggest Corrections

Similar questions

Z n + C u S O_{4} \to Z n S O_{4} + C u

E_{Z n / Z n^{2 +}}^{\circ} = 0.765 v o l t; E_{C u^{2 +} / C u}^{\circ} = 0.347 v o l t

C u {S O}_{4}

Z n + C u {S O}_{4} ⟶ Z n {S O}_{4} + C u

100 m l

0.05 M

C u {S O}_{4}

C u S O_{4} + Z n \to C u + Z n S O_{4}

Z n | Z n S O_{4} | | C u S O_{4} | C u

Join BYJU'S Learning Program