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Question

Match with the correct value of tanC×sinA in each case.

A
12
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B
35
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C
3/2
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Solution

Case(1):
tan C × sin A
tan 60×sin 30
= 3× 12
= 32

Case(2):
tan C × sin A
tan 45×sin 45
= 1×12
= 12

Case(3):
tan C × sin A
tan 37×sin 53
= 34 × 45
= 35

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