Matching type questions:
Column−IColumn−II(P) Number of points on the hyperbola xy=c2fromwhich(1)1two tangents drawn to the ellipse x2a2+y2b2=1(where b<a<c) are perpendicular to each other is(Q) The constant term of the quadratic expression(2)0∑nk=2(x−1k−1)(x−1k),asn→∞(R) f(x)=[tanx[cotx]],xϵ[π12,π2] (where[.]represents(3)3the greatest integer function) then the number of points,where f(x) is not continuous is(S) Equation of plane through (2,−1,0),(3,−4,5) and(4)4parallel to a line whose direction cosine proportional to 2,3,4is9x−2y−3z=5k then k is
P -2, Q-4. R-1, S-3
Required number of points will be equal to number of real points of intersection of the given hyperbola and the director circle of the given ellipse.
As director circle is x2+y2=a2+b2<2c2 which does not intersect the hyperbola xy = c^2.
which does not intersect the hyperbola xy=c2.
(B) constant term =∑nk=21k(k−1)=∑nk=2(1k−1−1k)=−1−1n
As n→∞
constant term →1
[cotx]=cotxifcotxϵI
<cotxifcotx/ϵI.⇒[tanx[cotx]]=1ifcotxϵI=0ifcotx/ϵI
so points of discontinuity are those where cotxϵI
As π12≤x<π2
0<cotx<2+√3
∴ number of points of discontinuity = 3.
(D) equation of plane through (2, -1, 0) is
a(x - 2) + b(y + 1) + c(z - 0) = 0 \\
As it passes through (3, -4, 5)
then a - 3b + 5c = 0 \\
Also 2a + 3b + c = 0
∴a−27=b6=c9
equation of plane
9(x−2)−2(y+1)−3z=0
or, 9x−2y−3z=20
∴ k=4.