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Question

A block and tackle system has the velocity ratio 3. A man can exert a pull of 200 kgf. If the effort end moves a distance 60 cm, what distance does the load move?

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Solution

Dear Student ,
Here in this case we know that ,
Effort×Displaement of effort arm=Load ×Displacement of load arm200×60=360×Displacement of load armDisplacement of load arm=200×60360=33·33 cm
Regards

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