Dear Student,
​Suppose a spherical body of radius r moves at speed v through a fluid of viscosity ƞ ,viscous force F acting on the body depends on r,v and ƞ .
According to the dimensional analysis we can write,
Let F = kravb ƞ​c
Where k is the dimensional less constant.
MLT-2 = kLa(LT-1)b(ML-1 T-1)c
On equating the coefficients of M,L,T on both sides we get :
a,b,c each = 1
hence F = krvÆž,
value of k = 6π,
hence stokes law becomes,
F = 6πÆžrv
This is the required viscous force
Regards