If -160-international -160-atomic -160-mass -160-of -160-magnesium -160-is -160-24-31- -160-The -160-mass -160-of -160-one -160-atom -160-of -160-magnesium -160-weighs-1- -160-40-34 -160- -215- -160-10-24 -160-g2- -160-4-03 -160- -215- -160-10-24 -160-g3- -160-16-64 -160- -215- -160-10-2 -160-g4- -160-1-66 -160- -215- -160-10-23 -160-g

Dear student , 1 mole Mg = 24 .31 g nbsp; 6.022 * 10 nbsp;23 atom = 24.31 1 atom = 24.31 / 6.022 * 10 nbsp;23 Mass of 1 atom = 4.03 * 10 nbsp; 23 g nb ...

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Byju's Answer

Standard IX

Physics

Fundamental and Derived Units

If #160;int...

Question

$I f i n t e r n a t i o n a l a t o m i c m a s s o f m a g n e s i u m i s 24.31 . T h e m a s s o f o n e a t o m o f m a g n e s i u m w e i g h s : 1) 40.34 \times 10^{- 24} g 2) 4.03 \times 10^{- 24} g 3) 16.64 \times 10^{- 2} g 4) 1.66 \times 10^{- 23} g$

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Solution

Dear student ,

1 mole Mg = 24 .31 g
6.022 * 10 ²³ atom = 24.31
1 atom = 24.31 / 6.022 * 10 ²³
**Mass of 1 atom = 4.03 * 10 ^-23 g**

The answer is option (2)
Regards

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If international atomic mass of magnesium is 24.31. The mass of one atom of magnesium weighs:1) 40.34 × 10-24 g2) 4.03 × 10-24 g3) 16.64 × 10-2 g4) 1.66 × 10-23 g

Dear student , 1 mole Mg = 24 .31 g 6.022 * 10 23 atom = 24.31 1 atom = 24.31 / 6.022 * 10 23 Mass of 1 atom = 4.03 * 10 -23 g The answer is option (2) Regards

$I f i n t e r n a t i o n a l a t o m i c m a s s o f m a g n e s i u m i s 24.31 . T h e m a s s o f o n e a t o m o f m a g n e s i u m w e i g h s : 1) 40.34 \times 10^{- 24} g 2) 4.03 \times 10^{- 24} g 3) 16.64 \times 10^{- 2} g 4) 1.66 \times 10^{- 23} g$

Dear student ,

1 mole Mg = 24 .31 g
6.022 * 10 ²³ atom = 24.31
1 atom = 24.31 / 6.022 * 10 ²³
**Mass of 1 atom = 4.03 * 10 ^-23 g**

The answer is option (2)
Regards