Question

$Ify=\frac{1}{\cos \theta +\mu \sin \theta },thenthevalueof\frac{dy}{d\theta }is$
(1) $-\sin \theta +\mu \cos \theta$ (2) $\frac{-1}{(\cos \theta +\mu \sin \theta {)}^2}$
(3) $\frac{\sin \theta -\mu \cos \theta }{(\cos \theta +\mu \sin \theta {)}^2}$ (4) $\frac{\mu \cos \theta -\sin \theta }{(\cos \theta +\mu \sin \theta {)}^2}$

Answer 1

$$\begin{gathered} Dearstudent, \\ \frac{d}{dx}\left(\frac{u}{v}\right)=\frac{v{\displaystyle \frac{du}{dx}}-u{\displaystyle \frac{dv}{dx}}}{v^2} \\ sou\sin gthisformulawehave, \\ \frac{dy}{d\theta }=\frac{0-1(-\sin \theta +\mu \cos \theta )}{(\cos \theta +\mu \sin \theta {)}^2}=\frac{\sin \theta -\mu \cos \theta }{(\cos \theta +\mu \sin \theta {)}^2} \\ Regards \end{gathered}$$