In -160-successive -160-emission -160-of -160- -945- -160-and -160- -946- -160-particles- -160-the -160-number -160-of -160- -945- -160-and -160- -946- -160-particles -160-should -160-be -160-emitted -160-for -160-the -160-conversion -160-of -160-U23892 -160-to -160-P82b206 -160-are-a- -160-7 -945- -160-5 -946-b- -160-6 -945- -160-4 -946-c- -160-4 -945- -160-3 -946-d- -160-8 -945- -160-6 -946-

Dear student When an alpha particle is emitted nbsp;the atomic mass no. decrease by 4 and atomic no. decrease by 2 unit and when a beta particle nbsp;is em ...

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Byju's Answer

Standard X

Physics

Beta Decay

In #160;suc...

Question

$I n s u c c e s s i v e e m i s s i o n o f α - a n d β - p a r t i c l e s, t h e n u m b e r o f α - a n d β - p a r t i c l e s s h o u l d b e e m i t t e d f o r t h e c o n v e r s i o n o f {}_{92}U^{238} t o {}_{82}P b^{206} a r e (a) 7 α, 5 β (b) 6 α, 4 β (c) 4 α, 3 β (d) 8 α, 6 β$

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Solution

Dear student

When an alpha-particle is emitted the atomic mass no. decrease by 4 and atomic no. decrease by 2 unit and when a beta-particle is emitted atomic no. increase by one unit and atomic mass no. remain unchanged.

the difference in mass no. = 238-206 = 32
So alpha partical = 32/4 = 8
after emission of 8 alpha particle = ₇₆U²⁰⁶
then after emmision of 6 beta-particle it will be ₈₂U²⁰⁶

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In successive emission of α- and β- particles, the number of α- and β- particles should be emitted for the conversion of U23892 to P82b206 are(a) 7α, 5β(b) 6α, 4β(c) 4α, 3β(d) 8α, 6β